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344 lines
9.7 KiB
344 lines
9.7 KiB
// Copyright 2009 The Go Authors. All rights reserved. |
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// Use of this source code is governed by a BSD-style |
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// license that can be found in the LICENSE file. |
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package flate |
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import ( |
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"math" |
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"sort" |
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) |
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// hcode is a huffman code with a bit code and bit length. |
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type hcode struct { |
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code, len uint16 |
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} |
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type huffmanEncoder struct { |
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codes []hcode |
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freqcache []literalNode |
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bitCount [17]int32 |
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lns byLiteral // stored to avoid repeated allocation in generate |
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lfs byFreq // stored to avoid repeated allocation in generate |
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} |
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type literalNode struct { |
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literal uint16 |
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freq int32 |
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} |
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// A levelInfo describes the state of the constructed tree for a given depth. |
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type levelInfo struct { |
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// Our level. for better printing |
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level int32 |
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// The frequency of the last node at this level |
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lastFreq int32 |
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// The frequency of the next character to add to this level |
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nextCharFreq int32 |
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// The frequency of the next pair (from level below) to add to this level. |
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// Only valid if the "needed" value of the next lower level is 0. |
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nextPairFreq int32 |
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// The number of chains remaining to generate for this level before moving |
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// up to the next level |
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needed int32 |
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} |
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// set sets the code and length of an hcode. |
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func (h *hcode) set(code uint16, length uint16) { |
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h.len = length |
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h.code = code |
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} |
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func maxNode() literalNode { return literalNode{math.MaxUint16, math.MaxInt32} } |
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func newHuffmanEncoder(size int) *huffmanEncoder { |
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return &huffmanEncoder{codes: make([]hcode, size)} |
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} |
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// Generates a HuffmanCode corresponding to the fixed literal table |
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func generateFixedLiteralEncoding() *huffmanEncoder { |
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h := newHuffmanEncoder(maxNumLit) |
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codes := h.codes |
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var ch uint16 |
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for ch = 0; ch < maxNumLit; ch++ { |
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var bits uint16 |
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var size uint16 |
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switch { |
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case ch < 144: |
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// size 8, 000110000 .. 10111111 |
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bits = ch + 48 |
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size = 8 |
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break |
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case ch < 256: |
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// size 9, 110010000 .. 111111111 |
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bits = ch + 400 - 144 |
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size = 9 |
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break |
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case ch < 280: |
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// size 7, 0000000 .. 0010111 |
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bits = ch - 256 |
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size = 7 |
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break |
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default: |
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// size 8, 11000000 .. 11000111 |
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bits = ch + 192 - 280 |
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size = 8 |
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} |
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codes[ch] = hcode{code: reverseBits(bits, byte(size)), len: size} |
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} |
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return h |
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} |
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func generateFixedOffsetEncoding() *huffmanEncoder { |
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h := newHuffmanEncoder(30) |
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codes := h.codes |
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for ch := range codes { |
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codes[ch] = hcode{code: reverseBits(uint16(ch), 5), len: 5} |
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} |
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return h |
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} |
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var fixedLiteralEncoding *huffmanEncoder = generateFixedLiteralEncoding() |
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var fixedOffsetEncoding *huffmanEncoder = generateFixedOffsetEncoding() |
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func (h *huffmanEncoder) bitLength(freq []int32) int { |
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var total int |
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for i, f := range freq { |
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if f != 0 { |
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total += int(f) * int(h.codes[i].len) |
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} |
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} |
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return total |
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} |
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const maxBitsLimit = 16 |
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// Return the number of literals assigned to each bit size in the Huffman encoding |
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// |
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// This method is only called when list.length >= 3 |
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// The cases of 0, 1, and 2 literals are handled by special case code. |
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// |
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// list An array of the literals with non-zero frequencies |
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// and their associated frequencies. The array is in order of increasing |
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// frequency, and has as its last element a special element with frequency |
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// MaxInt32 |
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// maxBits The maximum number of bits that should be used to encode any literal. |
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// Must be less than 16. |
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// return An integer array in which array[i] indicates the number of literals |
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// that should be encoded in i bits. |
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func (h *huffmanEncoder) bitCounts(list []literalNode, maxBits int32) []int32 { |
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if maxBits >= maxBitsLimit { |
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panic("flate: maxBits too large") |
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} |
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n := int32(len(list)) |
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list = list[0 : n+1] |
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list[n] = maxNode() |
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// The tree can't have greater depth than n - 1, no matter what. This |
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// saves a little bit of work in some small cases |
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if maxBits > n-1 { |
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maxBits = n - 1 |
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} |
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// Create information about each of the levels. |
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// A bogus "Level 0" whose sole purpose is so that |
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// level1.prev.needed==0. This makes level1.nextPairFreq |
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// be a legitimate value that never gets chosen. |
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var levels [maxBitsLimit]levelInfo |
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// leafCounts[i] counts the number of literals at the left |
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// of ancestors of the rightmost node at level i. |
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// leafCounts[i][j] is the number of literals at the left |
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// of the level j ancestor. |
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var leafCounts [maxBitsLimit][maxBitsLimit]int32 |
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for level := int32(1); level <= maxBits; level++ { |
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// For every level, the first two items are the first two characters. |
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// We initialize the levels as if we had already figured this out. |
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levels[level] = levelInfo{ |
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level: level, |
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lastFreq: list[1].freq, |
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nextCharFreq: list[2].freq, |
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nextPairFreq: list[0].freq + list[1].freq, |
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} |
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leafCounts[level][level] = 2 |
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if level == 1 { |
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levels[level].nextPairFreq = math.MaxInt32 |
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} |
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} |
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// We need a total of 2*n - 2 items at top level and have already generated 2. |
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levels[maxBits].needed = 2*n - 4 |
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level := maxBits |
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for { |
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l := &levels[level] |
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if l.nextPairFreq == math.MaxInt32 && l.nextCharFreq == math.MaxInt32 { |
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// We've run out of both leafs and pairs. |
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// End all calculations for this level. |
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// To make sure we never come back to this level or any lower level, |
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// set nextPairFreq impossibly large. |
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l.needed = 0 |
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levels[level+1].nextPairFreq = math.MaxInt32 |
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level++ |
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continue |
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} |
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prevFreq := l.lastFreq |
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if l.nextCharFreq < l.nextPairFreq { |
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// The next item on this row is a leaf node. |
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n := leafCounts[level][level] + 1 |
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l.lastFreq = l.nextCharFreq |
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// Lower leafCounts are the same of the previous node. |
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leafCounts[level][level] = n |
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l.nextCharFreq = list[n].freq |
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} else { |
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// The next item on this row is a pair from the previous row. |
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// nextPairFreq isn't valid until we generate two |
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// more values in the level below |
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l.lastFreq = l.nextPairFreq |
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// Take leaf counts from the lower level, except counts[level] remains the same. |
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copy(leafCounts[level][:level], leafCounts[level-1][:level]) |
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levels[l.level-1].needed = 2 |
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} |
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if l.needed--; l.needed == 0 { |
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// We've done everything we need to do for this level. |
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// Continue calculating one level up. Fill in nextPairFreq |
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// of that level with the sum of the two nodes we've just calculated on |
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// this level. |
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if l.level == maxBits { |
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// All done! |
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break |
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} |
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levels[l.level+1].nextPairFreq = prevFreq + l.lastFreq |
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level++ |
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} else { |
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// If we stole from below, move down temporarily to replenish it. |
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for levels[level-1].needed > 0 { |
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level-- |
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} |
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} |
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} |
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// Somethings is wrong if at the end, the top level is null or hasn't used |
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// all of the leaves. |
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if leafCounts[maxBits][maxBits] != n { |
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panic("leafCounts[maxBits][maxBits] != n") |
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} |
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bitCount := h.bitCount[:maxBits+1] |
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bits := 1 |
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counts := &leafCounts[maxBits] |
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for level := maxBits; level > 0; level-- { |
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// chain.leafCount gives the number of literals requiring at least "bits" |
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// bits to encode. |
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bitCount[bits] = counts[level] - counts[level-1] |
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bits++ |
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} |
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return bitCount |
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} |
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// Look at the leaves and assign them a bit count and an encoding as specified |
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// in RFC 1951 3.2.2 |
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func (h *huffmanEncoder) assignEncodingAndSize(bitCount []int32, list []literalNode) { |
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code := uint16(0) |
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for n, bits := range bitCount { |
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code <<= 1 |
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if n == 0 || bits == 0 { |
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continue |
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} |
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// The literals list[len(list)-bits] .. list[len(list)-bits] |
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// are encoded using "bits" bits, and get the values |
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// code, code + 1, .... The code values are |
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// assigned in literal order (not frequency order). |
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chunk := list[len(list)-int(bits):] |
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h.lns.sort(chunk) |
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for _, node := range chunk { |
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h.codes[node.literal] = hcode{code: reverseBits(code, uint8(n)), len: uint16(n)} |
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code++ |
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} |
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list = list[0 : len(list)-int(bits)] |
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} |
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} |
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// Update this Huffman Code object to be the minimum code for the specified frequency count. |
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// |
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// freq An array of frequencies, in which frequency[i] gives the frequency of literal i. |
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// maxBits The maximum number of bits to use for any literal. |
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func (h *huffmanEncoder) generate(freq []int32, maxBits int32) { |
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if h.freqcache == nil { |
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// Allocate a reusable buffer with the longest possible frequency table. |
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// Possible lengths are codegenCodeCount, offsetCodeCount and maxNumLit. |
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// The largest of these is maxNumLit, so we allocate for that case. |
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h.freqcache = make([]literalNode, maxNumLit+1) |
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} |
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list := h.freqcache[:len(freq)+1] |
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// Number of non-zero literals |
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count := 0 |
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// Set list to be the set of all non-zero literals and their frequencies |
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for i, f := range freq { |
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if f != 0 { |
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list[count] = literalNode{uint16(i), f} |
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count++ |
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} else { |
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list[count] = literalNode{} |
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h.codes[i].len = 0 |
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} |
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} |
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list[len(freq)] = literalNode{} |
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list = list[:count] |
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if count <= 2 { |
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// Handle the small cases here, because they are awkward for the general case code. With |
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// two or fewer literals, everything has bit length 1. |
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for i, node := range list { |
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// "list" is in order of increasing literal value. |
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h.codes[node.literal].set(uint16(i), 1) |
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} |
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return |
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} |
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h.lfs.sort(list) |
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// Get the number of literals for each bit count |
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bitCount := h.bitCounts(list, maxBits) |
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// And do the assignment |
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h.assignEncodingAndSize(bitCount, list) |
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} |
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type byLiteral []literalNode |
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func (s *byLiteral) sort(a []literalNode) { |
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*s = byLiteral(a) |
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sort.Sort(s) |
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} |
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func (s byLiteral) Len() int { return len(s) } |
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func (s byLiteral) Less(i, j int) bool { |
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return s[i].literal < s[j].literal |
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} |
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func (s byLiteral) Swap(i, j int) { s[i], s[j] = s[j], s[i] } |
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type byFreq []literalNode |
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func (s *byFreq) sort(a []literalNode) { |
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*s = byFreq(a) |
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sort.Sort(s) |
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} |
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func (s byFreq) Len() int { return len(s) } |
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func (s byFreq) Less(i, j int) bool { |
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if s[i].freq == s[j].freq { |
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return s[i].literal < s[j].literal |
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} |
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return s[i].freq < s[j].freq |
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} |
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func (s byFreq) Swap(i, j int) { s[i], s[j] = s[j], s[i] }
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