Python to generate nice looking SVG graph http://pygal.org/
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#!python
from itertools import chain, repeat, izip
import datetime
# from itertools recipes (python documentation)
def grouper(n, iterable, padvalue=None):
"""
>>> tuple(grouper(3, 'abcdefg', 'x'))
(('a', 'b', 'c'), ('d', 'e', 'f'), ('g', 'x', 'x'))
"""
return izip(*[chain(iterable, repeat(padvalue, n-1))]*n)
def reverse_mapping(mapping):
"""
For every key, value pair, return the mapping for the
equivalent value, key pair
>>> reverse_mapping({'a': 'b'}) == {'b': 'a'}
True
"""
keys, values = zip(*mapping.items())
return dict(zip(values, keys))
def flatten_mapping(mapping):
"""
For every key that has an __iter__ method, assign the values
to a key for each.
>>> flatten_mapping({'ab': 3, ('c','d'): 4}) == {'ab': 3, 'c': 4, 'd': 4}
True
"""
return dict(flatten_items(mapping.items()))
def flatten_items(items):
for keys, value in items:
if hasattr(keys, '__iter__'):
for key in keys:
yield (key, value)
else:
yield (keys, value)
def float_range(start=0, stop=None, step=1):
"""
Much like the built-in function range, but accepts floats
>>> tuple(float_range(0, 9, 1.5))
(0.0, 1.5, 3.0, 4.5, 6.0, 7.5)
"""
start = float(start)
while start < stop:
yield start
start += step
def date_range(start=None, stop=None, step=None):
"""
Much like the built-in function range, but works with dates
>>> my_range = tuple(date_range(datetime.datetime(2005,12,21), datetime.datetime(2005,12,25)))
>>> datetime.datetime(2005,12,21) in my_range
True
>>> datetime.datetime(2005,12,22) in my_range
True
>>> datetime.datetime(2005,12,25) in my_range
False
"""
if step is None: step = datetime.timedelta(days=1)
if start is None: start = datetime.datetime.now()
while start < stop:
yield start
start += step
# copied from jaraco.datetools
def divide_timedelta_float(td, divisor):
"""
Meant to work around the limitation that Python datetime doesn't support
floats as divisors or multiplicands to datetime objects
>>> one_day = datetime.timedelta(days=1)
>>> half_day = datetime.timedelta(days=.5)
>>> divide_timedelta_float(one_day, 2.0) == half_day
True
>>> divide_timedelta_float(one_day, 2) == half_day
False
"""
# td is comprised of days, seconds, microseconds
dsm = [getattr(td, attr) for attr in ('days', 'seconds', 'microseconds')]
dsm = map(lambda elem: elem/divisor, dsm)
return datetime.timedelta(*dsm)
def get_timedelta_total_microseconds(td):
seconds = td.days*86400 + td.seconds
microseconds = td.microseconds + seconds*(10**6)
return microseconds
def divide_timedelta(td1, td2):
"""
Get the ratio of two timedeltas
>>> one_day = datetime.timedelta(days=1)
>>> one_hour = datetime.timedelta(hours=1)
>>> divide_timedelta(one_hour, one_day) == 1/24.0
True
"""
td1_total = float(get_timedelta_total_microseconds(td1))
td2_total = float(get_timedelta_total_microseconds(td2))
return td1_total/td2_total
class TimeScale(object):
"Describes a scale factor based on time instead of a scalar"
def __init__(self, width, range):
self.width = width
self.range = range
def __mul__(self, delta):
scale = divide_timedelta(delta, self.range)
return scale*self.width